1860 United States presidential election in Delaware

1860 United States presidential election in Delaware

← 1856 November 6, 1860 1864 →

Nominee John C. Breckinridge John Bell Party Southern Democratic Constitutional Union Home state Kentucky Tennessee Running mate Joseph Lane Edward Everett Electoral vote 3 0 Popular vote 7,339 3,888 Percentage 45.54% 24.13%   Nominee Abraham Lincoln Stephen A. Douglas Party Republican Democratic Home state Illinois Illinois Running mate Hannibal Hamlin Herschel V. Johnson Electoral vote 0 0 Popular vote 3,822 1,066 Percentage 23.72% 6.61%

County Results Breckinridge   40-50%   50-60%

President before election James Buchanan Democratic Elected President Abraham Lincoln Republican

Elections in Delaware
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v t e

The 1860 United States presidential election in Delaware took place on November 6, 1860, as part of the 1860 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.

Delaware was won by the Southern Democratic candidate 14th Vice President of the United States John C. Breckinridge of Kentucky and his running mate Senator Joseph Lane of Oregon. They defeated the Constitutional Union candidate Senator John Bell of Tennessee and his running mate Governor of Massachusetts Edward Everett, Republican candidate Illinois Representative Abraham Lincoln and his running mate Senator Hannibal Hamlin of Maine as well as Democratic candidate 15th Senator Stephen A. Douglas of Illinois and his running mate 41st Governor of Georgia Herschel V. Johnson. Breckinridge won the state by a margin of 21.41%.

The Republicans ran a slate of electors for Lincoln, but did not nominate any candidates for other federal and state offices. The party instead endorsed the candidates of the People's Party, an anti-Democratic coalition that supported the Republican presidential ticket.^[1]